Showing posts with label Math Help. Show all posts
Showing posts with label Math Help. Show all posts

Friday, August 27, 2010

Help with online integrator


Introduction to solve online integral of a function:
In this article let me help you on online integrator. In calculus, an anti derivative, primitives or indefinite integral of a function f is a function F whose derivative is equal to f, i.e., F ′ = f. The process of solving for anti derivative is called anti differentiation (or indefinite integration) and its opposite function is called differentiation, which is the process of finding a derivative.
In online, we have to learn about different math problem and its solutions. It is the very useful for students. Online is best way for teaching math problems to the students. This could also help us on empirical probability

Friday, August 6, 2010

Properties of Logarithms

Introduction:
Today let me help you on Properties of Logarithms. We use logarithms to mark terms linking various forms of powers in a different form. If you can job self-assuredly with powers in dissimilar analysis you should have no problems conduct logarithms.

Three Properties of Logarithms

Following are the three properties of Logarithms.

Multiplication property:

The first property of logarithms is declare what is the rule when you multiply two values with the same base together

(x2 * x3) Recall that logarithm is exponents, and when you multiply, you are going to add the logarithms.

logc xy = logc x + logc y.

Division property:

The second property of logarithms are the law what time you divide two values by resources of the similar base is the way to subtract the exponents. Therefore, the law for division is the method to subtract the logarithms.This also helps in partial differentiation

The log of a calculate is the dissimilarity of the logs.

Logc (x/y) = logc x – logc y.

Raising to a Power property:

The third property of logarithms are what time you increase a quantity to a power, the law is that you multiply the exponents jointly. In logarithms properties the exponent scheduled the argument is the coefficient of the log.

logc xr = r * logc x.


Vertex Form.

Monday, July 26, 2010

Note on Meters to Inches

Meters to inches

In this section let me help you on meters to inches. Keep reading if you have anything to add or share .. do leave your comments.
Meter:
The metre (or meter), symbol m, is the base unit of length in the International System of Units (SI). It is defined as the distance travelled by light in a complete vacuum in 1/299,792,458 of a second.
Inch:
An inch is the name of a unit of length in a number of different systems, including Imperial units, and United States customary units.

Let us see how to convert meters to inches in this article.

Formula for meters to inches

1 meter = 39.3700787 inches
Meters to Inches – Examples:

Meters to inches – Example 1:

This will also help us on phosphorus cycle

Convert 5 Meters to inches?

Solution:

Step 1:

Formula for converting meters to inches:

1 meter = 39.3700787 inches

Step 2:
So to find 5 meter
Step 3:
Multiply 5 with 39.3700787 = 196.8503935
Step 4:
Therefore, 5 meter = 196.8503935 inches.

Friday, July 23, 2010

linear programming problems

In this lesson lets study on Linear Programming Problems. Before i help you on the problems let me show your on the basic.

Basic Concept of Linear Programming Problem

Objective Function: The Objective Function is a linear function of variables which is to be optimised i.e., maximised or minimised. e.g., profit function, cost function etc. The objective function may be expressed as a linear expression.

Constraints: A linear equation represents a straight line. Limited time, labour etc. may be expressed as linear inequations or equations and are called constraints.

Optimisation: A decision which is considered the best one, taking into consideration all the circumstances is called an optimal decision. The process of getting the best possible outcome is called optimization. Linear Programming

Solution of a LPP: A set of values of the variables x1, x2,�.xn which satisfy all the constraints is called the solution of the LPP

Feasible Solution: A set of values of the variables x1, x2, x3,�.,xn which satisfy all the constraints and also the non-negativity conditions is called the feasible solution of the LPP.

Optimal Solution: The feasible solution, which optimises (i.e., maximizes or minimizes as the case may be) the objective function is called the optimal solution. Important terms Convex Region and Non-convex Sets.

Tuesday, July 20, 2010

Help on Factorial Calculator

Factorial calculator:
This article discusses using the factorial calculator. In this factorial calculator makes it easy to solve the factorial of the number or data’s. Enter the number in factorial calculator and then press the button. After if you get the solutions. In the mathematic factorial of a positive integer n. The number n denoted by n!. The positive integers are less than (or) equal to n.
Note: factorial number 0 (zero) solution is 1 (one).
For example:
5! = 5 * 4 * 3 * 2 * 1 = 120
Some factorial example problems are given below:

Factorial Calculator-examples: This also help's us on matrices calculator

Example 1:
To find the factorial number 2.
Solution:
2! = 2 * 1 = 2.
The factorial solution is 2.

Wednesday, July 14, 2010

Help on Probability Questions

We have studied enough about what is probability and it's importance towards mathematics. Now i am going to help you in understanding few probability questions with the solutions. so that you can follow the same kind of steps for all the probability questions and learn it on your own.

Questions on Probability.

Here is some Statistics and Probability Question Answers , which will explain how to find the mean , median and mode for the series of numbers

Question:1 The median of prime numbers between 51 and 80.

Answer: 53, 59, 61, 67, 71, 73, 79
Median = Middle-most score
Median = 67

Question:2 The mean of 31 results is 60. If the mean of the first 16 results is 58 and that of the last 16 results is 62, find the 16th result.

Answer: The sum of 31 results = 60 x 31 = 1860
The sum of first 16 results = 58 x 16 = 928
The sum of second 16 results = 62 x 16 = 992
:.16th result = (928 + 992) - 1860 = 60
16th result = 60